Friday, July 30, 2010

'Pretty Little Liars' Ashley Benson: 'A huge secret gets out' in 'The Perfect Storm'

"Pretty Little Liars" penultimate episode, "The Perfect Storm," traps everyone at school. Ashley Benson tells Zap2it that it will not end well for one of the girls.
"A huge secret gets out for one of the main girls," says Benson. "We all have to take our SATs, so everybody's stuck at school. There's certain people that come into the school where we're all stuck. Detective Wilden, anytime he's around ... there's just a lot of things that happen that shouldn't ... It kind of destroys somebody."
Detective Wilden (Bryce Johnson) isn't the only problem in Hanna's life, though. She has a budding love triangle with her boyfriend Sean (Chuck Hittinger) and friend Lucas (Brendan Robinson).
"Right now [Hanna and Lucas are] trying their friendship. They know what it was like to be the outcasts ... she saw what Alison did to him, she's a huge support system for him," Benson explains. "I know a lot of the fans want us to become boyfriend/girlfriend. I have no idea what the writers are going to do, but Brendan is really great, so we'll see what happens."
When pressed to declare if Hanna actually has feelings for Lucas as more than a friend, Benson admits, "I think she's starting to have feelings for him, but she's just scared to let herself because of who he is. But since Alison's gone, she's a stronger person. She's more down-to-earth and not as stuck up as she was. She stands up to Mona now ... Hanna doesn't really care anymore about her status, she's more real and who she really is."
Benson also teases that there is a big event looming for Hanna in the last two "Pretty Little Liars" episodes before the midseason break.
"We have a lot of new characters that are being introduced in these last couple episodes ... that create problems. In the very last episode, there's a huge thing that happens for my character and it's going to change a lot about my storyline. It's really good."

Credit - zap2it.com
Kelli at Gossip Freak

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